given a mean number of events that happen within unit time (𝜆):
- the number of events occurring within that unit time has Poisson Distribution
- the time between events has Exponential Distribution
- the total time of 𝛼 events has Gamma Distribution
Probability Mass Function
𝐏(𝑋=𝑥) = 𝑒−𝜆(𝜆𝑥/𝑥!) for 𝑥 = 0, 1, 2, …
where:
- 𝜆 = frequency, mean number of events to happen in unit time
- 𝑒 = 2.7183… see number e (Euler’s number)
- 𝑥 = the number of “events” in question to happen in unit time
see: Deriving Poisson Distribution from Binomial Distribution
Expectation
𝐄[𝑋] = 𝜆
proof
- 𝐄[𝑋] = 𝛴0≤𝑥≤∞[𝑥𝑓(𝑥)]
- 𝐄[𝑋] = 𝛴0≤𝑥≤∞[𝑥𝑒-𝜆𝜆𝑥/𝑥!]
- 𝐄[𝑋] = 𝑒-𝜆𝛴0≤𝑥≤∞[𝑥𝜆𝑥/𝑥!]
- 𝐄[𝑋] = 𝑒-𝜆𝛴0≤𝑥≤∞[𝜆𝑥-1/(𝑥-1)!]𝜆
- 𝐄[𝑋] = 𝑒-𝜆𝑒𝜆𝜆 # via e taylor series
- 𝐄[𝑋] = 𝜆
Variance
𝑉𝑎𝑟(𝑋) = 𝜆
proof
Cumulative Distribution Function
𝐶𝐷𝐹(𝑋≤𝑥) = 𝛤(⌊𝑥+1⌋, 𝜆) / ⌊𝑥⌋!
where:
Moment Generating Function
Example
Suppose you knew that the mean number of calls to a fire station on a weekday is 8. What is the probability that on a given weekday there would be 11 calls? This problem can be solved using the following formula based on the Poisson distribution
𝜆 = 8, therefore PMF is
- 𝐏(𝑋=𝑥) = 𝑒−8(8𝑥/𝑥!)
what’s the probability that on a given weekday there would be 11 calls?
- 𝐏(𝑋=11) = 𝑒−8(811/11!)
- 𝐏(𝑋=11) = 0.072
Plot PMF given 𝜆=8, for 0≤𝑥≤12
/poisson-distribution/poisson-plot.png)
/poisson-distribution/poisson-variance-calculation-1.png)
/poisson-distribution/poisson-variance-calculation-2.png)